2,100-100x+.1x^2=0

Solution for 2,100-100x+.1x^2=0 equation:

2.100-100x+.1x^2=0

We add all the numbers together, and all the variables

.1x^2-100x+2.1=0

a = .1; b = -100; c = +2.1;
Δ = b2-4ac
Δ = -1002-4·.1·2.1
Δ = 9999.16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-100)-\sqrt{9999.16}}{2*.1}=\frac{100-\sqrt{9999.16}}{0.2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-100)+\sqrt{9999.16}}{2*.1}=\frac{100+\sqrt{9999.16}}{0.2}
$